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If cot^2 (x) = cot (x - y) cot(x - z)then show that cot (2x) = 1/2[cot(y) + cot(z)]

Vaibhav Gupta , 9 Years ago
Grade 11
anser 1 Answers
Lab Bhattacharjee

Last Activity: 9 Years ago

HINT:   use cot(A-B)=[cotB cotA+1]/[\cotB- cotA]

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