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if x^2 – 9 + | x+ sin a |

saurabh , 10 Years ago
Grade 12th pass
anser 2 Answers
Sher Mohammad

Last Activity: 10 Years ago

|x+sina|>0 for all x,

x^2-9 <0 for -3<x>3

since the function is symmetric,

for x>0
x^2-9+x+sin(a)
taking most least value of sin(a)=-1

x^2+x-10=0
(x+.5)^2-10.25=0
x+.5= sqrt(10.25)
=3.2-.5=2.7

so function will satisfy inequality for -2.7<x>2.7

sher mohammad
b.tech, iit delhi


saurabh

Last Activity: 10 Years ago

thank you

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