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In triangle ABC, show that sin 3A.cos3(B-C)+sin 3B.cos3(C-A)+sin 3C.cos3(A-B)=sin 3A. sin3B .sin3C

SANJIB KUMAR KUNDU , 3 Years ago
Grade 10
anser 1 Answers
Vikas Amritiya

Last Activity: 3 Years ago

Dear student please find attachment below 
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