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Maximum and minimum value of Sin^2(60-x)+sin^2(60+x)

Vishwas , 6 Years ago
Grade 10
anser 2 Answers
Deepak Kumar Shringi

Last Activity: 6 Years ago

562-1996_Capture.PNG562-911_Capture.PNG

Soumendu Majumdar

Last Activity: 6 Years ago

Dear student,
 sin^2(60-x) + sin^2(60 + x) = 1.5 cos^2 x + 0.5 sin^2 x 
= 1.5 (cos^2x) + 0.5 (1-cos^2 x)
= cos^2x + 0.5
So 0\leq cos^2 x\leq 1
Hence Minimum value = 0.5 = 1/2
Maximum value = 1.5 = 3/2
 
Hope it helps!
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