Prove that: a(cosb.cosc+cosa)=b(cosc.cosa+cosb)=c(cosa.cosb+cosc)
Anjani kumar , 8 Years ago
Grade 12th pass
Trigonometry> Prove that: a(cosb.cosc+cosa)=b(cosc.cosa...
2 Answers
Saurabh Koranglekar
Last Activity: 6 Years ago
Dear student
There must be more information about the question, kindly upload complete question
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There must be more information about the question, kindly upload complete question
Regards
Shreyash Kumar
Last Activity: 5 Years ago
a(cosB.cosC+cosA)
a/2 [cos(B+C)+cos(B-C)-2cos(B+C)]
a/2[cos(B-C)-cos(B+C)]
a[sinB.sinC]
ksinA.sinB.sinC
b[sinA.sinC]
b/2[cos(A-C)-cos(A+C)]
Adding and Subtracting cos(A+C) inside parenthesis
b/2[cos(A+C)+cos(A-C)-2cos(A+C)]
b[cosA.cosC-(-cosB)]
b[cosA.cosC+cosB]
a/2 [cos(B+C)+cos(B-C)-2cos(B+C)]
a/2[cos(B-C)-cos(B+C)]
a[sinB.sinC]
ksinA.sinB.sinC
b[sinA.sinC]
b/2[cos(A-C)-cos(A+C)]
Adding and Subtracting cos(A+C) inside parenthesis
b/2[cos(A+C)+cos(A-C)-2cos(A+C)]
b[cosA.cosC-(-cosB)]
b[cosA.cosC+cosB]
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