prove that sin2A+sin2B+sin2c=2(sinA+sinB+sinC)(1+cosA+cosB+cosC) if A+B+C=0

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prove that sin2A+sin2B+sin2c=2(sinA+sinB+sinC)(1+cosA+cosB+cosC) if A+B+C=0

prove that sin2A+sin2B+sin2c=2(sinA+sinB+sinC)(1+cosA+cosB+cosC) if A+B+C=0

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prove that sin2A+sin2B+sin2c=2(sinA+sinB+sinC)(1+cosA+cosB+cosC) if A+B+C=0

prove that sin2A+sin2B+sin2c=2(sinA+sinB+sinC)(1+cosA+cosB+cosC) if A+B+C=0

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