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Prove that: tan5x+tan3x/tan5x-tan3x=4cos2xcos4x

Kartik Sawant , 9 Years ago
Grade 12
anser 3 Answers
Latika Leekha

Last Activity: 9 Years ago

Hello student,
We first consider the L.H.S. and try to reach the R.H.S.
L.H.S = \frac{tan 5x + tan 3x}{tan 5x - tan 3x}
= \frac{\frac{sin 5x}{cos 5x}+\frac{sin 3x}{cos 3x}}{\frac{sin 5x}{cos 5x}-\frac{sin 3x}{cos 3x}}
= \frac{sin 5x cos 3x +sin 3x cos 5x}{sin 5x cos 3x - sin 3x cos 5x}
= \frac{sin (5x+3x)}{sin (5x-3x)}
(Using the formula sin A cos B + cos A sin B = sin (A+B) )
= \frac{sin 8x}{sin 2x}
= 2 sin 4x cos 4x/sin 2x
= 2(2 sin 2x cos 2x)cos 4x/sin 2x
= 4 cos 2x cos 4x.
= R.H.

Sai Sampath

Last Activity: 9 Years ago

=\frac{sin 5x cos 3x +sin 3x cos 5x}{sin 5x cos 3x - sin 3x cos 5x}\frac{\frac{sin 5x}{cos 5x}+\frac{sin 3x}{cos 3x}}{\frac{sin 5x}{cos 5x}-\frac{sin 3x}{cos 3x}}\frac{tan 5x + tan 3x}{tan 5x - tan 3x}(Using the formula sin A cos B + cos A sin B = sin (A+B)

\frac{sin (5x+3x)}{sin (5x-3x)} 
 = 2 sin 4x cos 4x/sin 2x= 2(2 sin 2x cos 2x)cos 4x/sin 2x= 4 cos 2x cos 4x.\frac{sin 8x}{sin 2x} 
 
 

Om

Last Activity: 3 Years ago

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Hare Krishna Hare Krishna Krishna Krishna Hare Hare
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nice solution of latika madam

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