Trigonometry> the is the formula of tan3A.................

the is the formula of tan3A...................................................???????????????

mohan , 8 Years ago

Grade 12

13 Answers

NAVEENKUMAR NAGIPOGU

Last Activity: 8 Years ago

dear mohan,

the formula of tan3a is the ratio of 3TANA-TAN ^3A – 1-TAN^2A.THIS IS ONLY FROM THE KNOWN AND TRUTH.FOR MORE DETAILS AND PROOVES AGAIN ASK.

Approved

N JYOTHEESWAR

Last Activity: 8 Years ago

writing tan(3A) as tan(2A + A) and use the expression for tan(A + B) to get. tan(2A + A) multiply with tan (a+b).we get tan 3a.

Prabhakar ch

Last Activity: 8 Years ago

Dear Mohan

Your answer is 3tana-tan^3a-1-tan^2a

All the best for your bright future...........................

Gowri sankar

Last Activity: 8 Years ago

HI MOHAN

The formula of TAN3 IS...............................................................................................................3tana-tan^3a-1-tan^2a.

raj

Last Activity: 8 Years ago

hallo mohan Your answer is 3tana-tan^3a-1-tan^2a.............................................................

T Dileep

Last Activity: 8 Years ago

hai mohan,formula of tan3x=(3tanx-tan^3x)/(1-3tan^2x)this is the formula of tan3x.tan3x formula in also represents another form.

sudarshan

Last Activity: 8 Years ago

the formula of tan3a is the ratio of 3TANA-TAN^3A-1-TAN^2A.This is the formula of tan3a.................

T.kumar

Last Activity: 8 Years ago

tan3a=3tan-tan^3a /1-3tan^2a. this is my answer .. all the best foyr your global furture...please approve..

Y MANJUNADH

Last Activity: 8 Years ago

mohan

the formula of tan3a is (3tana-tan³a)/1-3tan²a............................................it is used in trigonometry

manichandra

Last Activity: 8 Years ago

hi, i...indeed,to..need..your..help how..cn..i..prove..this, formula??? sin3a=3sina-4sin^3a cos3a=4cos^3-3cosa tan3a=3tan-tan^3a /1-3tan^2a. the..symbol.

BALAJI ANDALAMALA

Last Activity: 8 Years ago

$tan3A=tan(2A+A)=\frac{tan2A+tanA}{1-tan2A.tanA}$
$=\frac{\frac{2tanA}{1-tan^2A}+tanA}{1-\frac{2tanA}{1-tan^2A}.tanA}$
$=\frac{3tanA-tan^3A}{1-3tan^2A}$