Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to your problem.
We have,
FAB = P i
FBC = 2P j
FCD = 3P ( – i)
FDA = 4P ( – j)
Hence, resultant vector,
Fr = FAB + FBC + FCD + FDA
= (P i – 3P i) + (2P j – 4P j)
= – 2P i – 2P j
Hence, |Fr| = [(-2P)2 + (-2P)2]1/2
Hence, |Fr| = 2√2 P
Thanks and regards,
Kushagra