Aditya Gupta
Last Activity: 5 Years ago
as usual, vikas’ answer is wrong.
note that for any triangle ABC, AB + BC + CA= 0 where bold chars represent vectors.
now, if here we let a= BC= 3i + j – 2k, b= AC= – CA= –i + 3j + 4k then c= 4i – 2j – 6k= BC+CA= – AB= BA
so now median length bisecting c is= |b + (c/2)|
= |i + 2j + k|
= sqrt(1+4+1)
= sqrt(6)
kindly approve :=)
