Aditi Chauhan
Last Activity: 10 Years ago
Hello Student,
Please find the answer to your question
KEY CONCEPT : The question is based on Doppler’s effect where the medium through which the sound is travelling is also in motion.
By Doppler’s formula
v’ = v[ c + vm± v0/c + vm± vs] . . . . . . . . . . . . . . . . . (i)
NOTE : Sign convention for Vmis as follows : If medium is moving from s to O then +ve and vice versa. Similarly v0and vsare positive if these are directed from S to O and vice versa.
(a) Situation 1.
Velocity of sound in water c = √B/p = √2.088 x 109/103
c = 1445 m/s; vm = + 2m/s’ v0 = 0; vs = 10 m/s
∴ v’ = v [1445 + 2 – 0/1445 + 2 – 10] = v [1.007]
Now v = c ℷ = 1445/14.45 x 10-3 = 105 Hz
∴ v’ = 1.007 x 105 Hz
(b) Situation 2.
In air c = √y RT/M = 344 m/s
Applying formula (1)
v’ = v [344 – 5 – 0/344 – 5 – 10] = 1.03 x 105 Hz
Thanks
Aditi Chauhan
askIITians Faculty