A particle executing SHM from an extreme end of the path towards the centre is observed to be at distances x1, x2 and x3 from the centre, at the ends of three successive seconds. Its time period of oscillation is?
Rachit Bansal , 7 Years ago
Grade
1 Answers
Muntazir Wagay
Last Activity: 5 Years ago
X1=acosw×1=acosw
X2=axosw×2=acos2w
X3=acosw×3 =acos3w
Since
Cos(theta)=X1+X3/2X2
Therefore
Cos(theta) = acosw+acos3w/2acos2w
cosw(theta)= cosw
Theta = w
T= 2pie/theta
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