A simple pendulum undergoes SHM with time period T.How much time will it take to complete 3/8 oscillations?
Ankita Roy , 5 Years ago
Grade 11
Wave Motion> A simple pendulum undergoes SHM with time...
1 Answers
Arun
Last Activity: 5 Years ago
Time taken to complete one fourth oscillation T/ 4
so time to complete 1/8th oscillation from to extreme position is obtained from
y= a/2 = a cos cot = a cos 2 pai / T × t
0r cos Pai /3 = cos 2pai t/ T
t = (T/6) s
hence time to complete 3/8th oscillation
= T/4 + T/6
= 5T /12
y= a/2 = a cos cot = a cos 2 pai / T × t
0r cos Pai /3 = cos 2pai t/ T
t = (T/6) s
hence time to complete 3/8th oscillation
= T/4 + T/6
= 5T /12
Regards
Arun
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