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A tuning fork produces 4 beats per sec with one fork of frequency 288cps.a little wax is placed on the unknown fork and it produces 2 beats per second.the frequency of unknown fork is

sarojini , 6 Years ago
Grade 12
anser 1 Answers
Norman Manchu

Last Activity: 6 Years ago

Waxing implies loading of wax on the fork so as to decrease the frequency As we decrease the frequency of one of the unknown the number of beats produced also decrease
We can form two equations for the condition mentioned in the question but the equation which satisfies the waxing concept is this and the answer should be 292
288-n2=4\cdot

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