y = y1+y2= a [sin 2π (t/T – x/λ) + sin 2π (t/T + x/λ)]= a [2sin (2πt/T) cos(2πx/λ)]So, y = 2a cos (2πx/λ) sin (2πt/T)how was the second step in terms of COS arrived?
adarsh , 4 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 4 Years ago
Dear student
It is derived by using the formula
SinA + Sin B = 2 Sin(A+B)/2 * Cos(A-B)/2
Hope this will help
Good Luck
Cheers
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