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consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liquid of refractive index μ. A student finds that irrespective of what the incident angle is for a beam of light entering the liquid, the light reflected from the glass interface is never completely polarised. For this to happen, the minimum value of μ is√5 /√3\t3/√5\t5/√3\t4/3plz explain also

AD , 4 Years ago
Grade 12th pass
anser 2 Answers
Vikas TU

Last Activity: 4 Years ago

Dear student 
C
Sin C
1/mu
sin ib = ( 1 )
root ( mu ^ 2 + 1.5 ^ 2 )
mu ^ 2 + 1.5 ^2
mu 3/ root 5

Vikas TU

Last Activity: 4 Years ago

C is less than ib and c is criticle angle 
Sin c less than Sin ib a
Tan ib = mu ref = 1.5/mu
1/mu is less than 1.5 /root mu^2 + root(1.5)^2 
sin ib = 1 
root (mu^2) +1.5^2) is less than mu*1.5 
mu^2 + 1.5^2 is less than (mu*1.5)^2 
mu less than 3/ root5 

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