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If one of two identical slots producing interference in young`s experiment is covered with glass so that the light intensity passing through it is reduced to 50% find the ratio of the maximum and minimum intensity of the fridge in the interference pattern.

Sparsh , 6 Years ago
Grade 12
anser 2 Answers
Khimraj

Last Activity: 6 Years ago

I1/I2 = 2
Imax/Imin = [(\sqrt{I_{1}^{}} +\sqrt{I_{2}^{}})/(\sqrt{I_{1}^{}} – \sqrt{I_{2}^{}})]2 = [(\sqrt{I_{2}/I_{1}} +1)/(\sqrt{I_{2}/I_{1}} – 1 )]2
              = [(2+1)/(2-1)]2 = 9.
Hope it clears.If you like answer then please approve it.

Romy

Last Activity: 6 Years ago

I1/I2 = 2Imax/Imin = [(\sqrt{I_{1}^{}} +\sqrt{I_{2}^{}})/(\sqrt{I_{1}^{}} – \sqrt{I_{2}^{}})]2 = [(\sqrt{I_{2}/I_{1}} +1)/(\sqrt{I_{2}/I_{1}} – 1 )]2 = [(√2+1)/(√2-1)]2 = (3+2√2)/(3-2√2).

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