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The topic of three dimensional geometry is quite important and a bit complicated as compared to its counterpart two dimensional geometry. One of the ways of describing a 3D object is by approximating or assuming its shape as a mesh of triangles. A triangle is generally defined by three vertices wherein the positions of the vertices are described by the coordinates x, y and z.
The major heads that are included in 3D coordinate geometry are the direction ratios and direction cosines of a line segment.
The direction cosines are the cosines of the angles between a line and the coordinate axis. If we have a vector (a, b, c) in three dimensional space, then the direction cosines of the vector are defined as
cos α = a/ √(a2 + b2 + c2)
cos β = b/ √(a2 + b2 + c2)
If l, m and n are the direction cosines then the direction ratios say a, b and c are given by
l = ± a/√ Σa2 |
m = ± b/√ Σa2 |
n = ± c/√ Σa2 |
Some Key Points:
While the direction cosines of a line segment are always unique, the direction ratios are never unique and in fact they can be infinite in number.
If the direction cosines of a line are l, m and n then they satisfy the relation l2 + m2 + n2 = 1.
If the direction cosines of a line segment AB are (l, m, n) then those of line BA will be (-l, -m, -n).
Let us assume that θ is the angle between the two lines say AB and AC whose direction cosines are l1, m1 and n1 and l2, m2 and n2 then
cos θ = l1l2 + m1m2 + n1n2
Also if the direction ratios of two lines a1, b1 and c1 and a2, b2 and c2 then the angle between two lines is given by
cos θ = (a1a2 + b1b2 + c1c2)/ √( a12 + b12 + c12) . √ (a22 + b22 + c22)
When the two lines are perpendicular, the angle between the lines is 90° which gives the condition of perpendicularity as
l1l2 + m1m2 + n1n2 = 0
or this implies a1a2 + b1b2 + c1c2 = 0.
Similarly, when the two lines are parallel, the angle between them i.e. θ = 0.
This gives l1/l2 = m1/m2 = n1/n2
This also gives a1/a2 = b1/b2 = c1/c2
What is the projection of a line segment on a given line?
Suppose we have a line segment joining the points P (x1, y1, z1) and Q(x2, y2, z2), then the projection of this line on another line having direction cosines as l, m, n is AB = l(x2-x1) + m + m(y2-y1) + n(z2-z1).
A sphere is basically a circle in three dimensions. Just as a circle, sphere is also perfectly round and is defined as the locus of points that lie at the same distance say ‘r’ from a fixed point in three dimensional space. This ‘r’ is called as the radius of the sphere and this fixed point is called the center of the sphere. The general equation of sphere in 3D is
(x-a)2 + (y-b)2 + (z-c)2 = r2, where (a, b, c) is the center and r is the radius.
Illustration: The number of all possible triplets (a1, a2, a3) such that a1 + a2 cos(2x) + a3 sin2x = 0 for all x is zero/infinite/one/ three?
Solution: The given condition is a1 + a2 cos(2x) + a3 sin2x = 0
If we put x = 0 and x = π/2 we get
a1 + a2 = 0 and a1 - a2 + a3 = 0
Hence, a2 = - a1 and a3 = a2 – a1 = -2a1
And so this leads us to the equation of the form
a1 – a1 cos(2x) - 2a1 sin2x = 0 for all x
or a1 (1 – cos(2x) - 2 sin2x) = 0 for all x
which is satisfied for all values of a1
Hence, infinite number of triplets (a1-a1-2a1) are possible.
Illustration: Find the value of k such that (x-4)/1 = (y-2)/1 = (z-k)/2 lies in the plane 2x - 4y + z = 7.
Solution: Given equation of the straight line is
(x-4)/1 = (y-2)/1 = (z-k)/2
Since the line lies in the plane 2x - 4y + z = 7
Hence, the point (4, 2, k) must satisfy the plane which yields
8-8+k = 7
Hence, k = 7.
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