Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
The number of telephone calls received at an exchange per interval for 250 successive one- minute intervals are given in the following frequency table:
Compute the mean number of calls per interval.
Let be assumed mean (A) = 3
Mean number of cells = 3 + 135/250 = 885/250 = 3.54
Five coins were simultaneously tossed 1000 times, and at each toss the number of heads was observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.
Let the assumed mean (A) = 2
Mean number of per toss = 2 + 470/1000 = 2 + 0.47 = 2.47
The following table gives the number of branches and number of plants in the garden of a school.
Calculate the average number of branches per plant.
Let the assumed mean (A) = 4
Average number of branches per plant = 4 + (-77/200) = 4 -77/200 = (800 -77)/200 = 3.615
The following table gives the number of children of 150 families in a village
Find the average number of children per family.
Solution:
Average number of children for family = 2 + 52/150 = (300 +52)/150 = 352/150 = 2.35 (approx)
The marks obtained out of 50, by 102 students in a physics test are given in the frequency table below:
Find the average number of marks.
The number of students absent in a class was recorded every day for 120 days and the information is given in the following
Find the mean number of students absent per day.
Let mean assumed mean (A) = 3
Mean number of students absent per day = 3 + 63/120 = (360 + 63)/120 = 423/120 = 3.53
In the first proof of reading of a book containing 300 pages the following distribution of misprints was obtained:
Find the average number of misprints per page.
Average number of misprints per day = 2 + (- 381/300) = (600-381)/300 = 219/300 = 0.73
Find the mean from the following frequency distribution of marks at a test in statistics:
Find the average number of accidents per worker.
Average no of accidents per day workers ⟹ x + (-187/160) = 133/160 = 0.83
Let the assumed mean (A) = 25
Mean = 25 + (-1170)/400
= 22.075
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Chapter 7: Statistics Exercise – 7.1...
Chapter 7: Statistics Exercise – 7.4...
Chapter 7: Statistics Exercise – 7.3...
Chapter 7: Statistics Exercise – 7.5...
Chapter 7: Statistics Exercise – 7.6...