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A particle is projected in vertical plane such that after 5 seconds its velocity becomes horizontal. The maximum height attained by the projectile from point of projection is n3 m. The value of n is _______. (g = 10 m/s2)

Dhyey , 2 Years ago
Grade 11
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Forum 2

Last Activity: 1 Year ago

Hello student

Velocity of projectile=62+82​=100​=10ms−1
Angle of projectileθ=tan−168​=53∘
Range of projectile is given byR=gu2sin2θ​
R=10100×sin106∘​=9.6m
hope you find the answer helpful

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