A particle is projected in vertical plane such that after 5 seconds its velocity becomes horizontal. The maximum height attained by the projectile from point of projection is n3 m. The value of n is _______. (g = 10 m/s2)
Dhyey , 2 Years ago
Grade 11
1 Answers
Forum 2
Last Activity: 1 Year ago
Hello student
Velocity of projectile=62+82=100=10ms−1 Angle of projectileθ=tan−168=53∘ Range of projectile is given byR=gu2sin2θ R=10100×sin106∘=9.6m hope you find the answer helpful
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