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A thin rod of mass m and length L is pivoted at one end.Initially, the rod makes an angle of 60 with thevertical and is then released. Calculate the mgnitude and direction of the force on the pivot, when the rod is horizontal

shruti , 8 Years ago
Grade 12
anser 1 Answers
Piyush Kumar Behera

Last Activity: 8 Years ago

I am only giving the procedure ,how to solve,because it is very difficult for me to type the latex and the equations.
In this question first of all calculate the angular velocity when the rod becomes horizontal by energy conservation.this can be done by :
decrease in potential energy of centre of mass =gain in rotational kinetic energy.
then the force on the pivot =forc eexerted by the pivot on the rod=mw2r.
so you get the result.

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