consider the radius of deuterium and tritium to be approximately 1.5*10^-15m each and that for the deuterium-tritium fusion reaction,the mass defect is approximately 18 MeV.Then,A) kinetic energy needed to overcome coulomb repulsion is approximately 8*10^-14 J.B) the temperature to which the gases must be heated to initiate reaction is of the order of 10^9 K.C)the amount of energy liberated in the reaction is approximately 18 MeV.D) mass defect involved in the reaction is 0.0123 amu.give the correct answer along with proper explanation and if u think that suppose options b and c are correct and a is not correct,then plz tell why a is not corrrect..expecting a good and early reply..

Amit Saxena , 10 Years ago

Grade upto college level