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Find the maximum kinetic energy of the photoelectrons ejected when light of wavelength 350 nm is incident on a cesium surface. Work function of cesium = 1.9 eV.

Hrishant Goswami , 10 Years ago
Grade 10
anser 1 Answers
Deepak Patra

Last Activity: 10 Years ago

Sol. λ = 350 nn = 350 * 10^-9 m ∅ = 1.9 eV Max KE of electrons =- =hC/λ - ∅ = 6.63 * 10^-34 *3 * 10^8/350 * 10^-9 * 1.6 * 10^-19 = 1.65 ev = 1.6 ev.

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