Find the maximum magnitude of the linear momentum of a photoelectron emitted when light of wavelength 400 nm falls on a metal having work function 2.5 eV.
Radhika Batra , 10 Years ago
Grade 11
1 Answers
Aditi Chauhan
Last Activity: 10 Years ago
Sol. Energy of photoelectron
⇒ ½ mv^2 = hc/λ – hv base 0 = 4.14 * 10^-15 * 3 *10^8/4 * 10^-7 – 2.5 ev = 0.605 ev.
We known KE = P2/2m ⇒ P^2 = 2m * KE.
P^2 = 2 * 9.1 * 10^-31 * 0.605 * 1.6 * 10^-19
P = 4.197 * 10^-25 kg – m/s
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free