Vikas TU
Last Activity: 7 Years ago
Dear Student,0.693/t1/2 = k
t1/2= half life
k=disintegration or rot consistent
=>0.693/30 = k
=>k=0.0231
k=2.303log(a/a-x)/t
a=initial sum
a-x= sum left after deterioration
t=time of rot
=>0.0231=2.303log(108/108-x)/15
=>108/108-x=1.41
=>Amount left=108-x=7,09,21,986 nuclei.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)