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The displacement of a particle is represented by the following equation, s=3t3+7t2+5t+8s=3t^3+7t^2+5t+8, where s is in m and t is in see. The acceleration of the particle at t=1st=1s is

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Arka Kesh , 8 Years ago
Grade 11
anser 1 Answer
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ADITYA

Last Activity: 8 Years ago

First of all differentiate and obtain v then again differentiate and obtain a
On differentiating s we get v=9t^2+14t+5
Again differentiate a=18t+14
Put t=1
18+14=32ms^2 =a

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