The distance traveled by an object along the axes are given by x=2t², y = t² – 4, z = 3 t – 5. Whatis the initial velocity of the particle?
Monal Kala , 7 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 7 Years ago
Dear Student,
AAs given in the qstn., x=2t2 (dx/dt)t=0=Vx0= initial velocity along x-axis= 4t = 4x0 = 0 y=t2-4 (dy/dt)t=0=Vy0= initial velocity along y axis = 2t = 0 z=3t-5 (dz/dt)t=0=Vz0= initial velocity along z axis = 3
Initial resultant velocity= 0i+0j+3k =3k (cap).
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