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The energy required to remove an electron from M shell of H-atom is 1.51 eV, then the energy of the first excited state will be:-1.51 eV\t+1.51 eV\t-3.4 eV\t-13.6 eV

Radhika , 7 Years ago
Grade 12th pass
anser 1 Answers
Jotin Thingnam

Last Activity: 7 Years ago

Energy =-13.6/n2Where n= energy levelFirst excitation means, n=2Therefore, E= -13.6/4 eV = -3.4 eV

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