Two identical photocathodes receive light of frequencies x & y.If the velocities of the of the photoelectrons (of mass m)coming out are x & y,then(1) x-y = [2h/m(x-y)]1/2 (2) x2 - y2 =2h/m(x-y)(3) x+y = [2h/m(x-y)]1/2 (4) x2 + y2 =2h/m(x-y)
Navjyot Kalra , 11 Years ago
Grade 10
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