Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Find the range of:
f(x)=ιsinxι+ιcosxι, 0≤x≤π
where ιxι represents modulus of x.
Hi Menka,
Here you split the domain into two parts,
0≤x≤Π/2------------ Domain(1) and Π/2≤x≤Π----------Domain(2).
In D1, the function becomes f(x) = sinx+cosx = (√2)*(sin(x+Π/4),
In this domain sin(x+pi/4) lies in [1/√2,1]
Hence f(x) will lie in the range [1,√2].
Next in D2, the function becoemes f(x) = sinx - cosx = root(2)*sin(x-pi/4)
In this domain sin(x-pi/4) again lies in [1/√2,1]
Hence f(x) will lie in [1,√2].
Hence the range of this function is [1,√2].
Hope that helps.
All the best,
Regards,
Ashwin (IIT Madras).
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !