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The equation of the circle passing through (1,1) & points of intersection of x2+y2+13x-3y = 0 & 2x2+2y2 + 4x-7y-25 = 0 is??
Take the equation of the circle as x2+y2+13x-3y + k(2x2+2y2 + 4x-7y-25) = 0 where k is an arbitrary real no.
Put the values of the point (1,1) in the equation and find the value of k then rewrite this equation with the value of k and solve to get the eq.
k=1/2
and eqn is 4x2 + 4y2 + 30x - 33y - 25 = 0
why u put 1,1 inplace of x & y??
It is given in the question that the circle we are finding passes through (1,1) so i put them so as to satisfy the equation and find the value of k. Once the value of k is known question is over buddy.
If u liked my answer please approve it.
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