sabu ram
Last Activity: 3 Years ago
Heat absorbed, Q1=1000J
Heat rejected, Q2=600J
Temperature of reservoir, T1=127°C=127+273=400K
To find:
Efficiency of the engine, η=?
Temperature of sink, T2=?
Amount of useful work done per cycle, W=?
We know,
Efficiency of Carnot engine can be found be using the following formula,
η=Q1Q1−Q2=10001000−600=0.4 or 40%
Hence, the efficiency of the engine is 40%
We know, Efficinecy of carnot engine is also equal to
η=T1T1−T2∴0.4=400400−T2⟹400−T2=160⟹T2=400−160=240K or 240−273=−33°C
Hence, the temperature of the sink is -33°C.
We know,
W=Q1−Q2=1000−600=400J
Hence the amount of useful work done during each cycle is 400J.
