Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2So4 in 2 litre of water at 25°C, assuming that it is completely dissociated.

Question

Arun · Answer

Mass of K2SO4, w = 25 mg = 0.025g (use 1 g = 1000 mg ) Volume V = 2 liter T = 25 + 273 = 298 K The reaction of dissociation of K2SO4 K2SO4 → 2K+ + SO42- Number if ions produced = 2+ 1 = 3 So pi = i w RT/Mv Substituting the values and calculationg we get, π= 5.27 × 10-3 atm

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Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2So4 in 2 litre of water at 25°C, assuming that it is completely dissociated.

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2So4 in 2 litre of water at 25°C, assuming that it is completely dissociated.

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Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2So4 in 2 litre of water at 25°C, assuming that it is completely dissociated.

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2So4 in 2 litre of water at 25°C, assuming that it is completely dissociated.

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